====== Chess - Programming - LSB (Least Significant Bit) ====== The least significant bit (LSB) is the bit position of the __first__ bit set in a value. There are many ways to determine the LSB, but the goal is to do that as quickly as possible. * Due to the number of Chess positions possible, many millions, even a small saving for the lookup of the LSB can provide much further lookups in the same time. ---- ulong i = 18; // (10010) **NOTE:** The LSB would be the 2 (or 1 if we are counting position from 0). ---- ===== Using Bit-wise operations ===== ulong lsb = x & ~(x-1); ---- ===== Using Bit Manipulation ===== UINT64 countTrailingZeros(UINT64 input) { if (input == 0) return 64; UINT64 n = 0; if ((input & 0xFFFFFFFF) == 0) { n = 32; input = input >> 32; } if ((input & 0xFFFF) == 0) { n = n + 16; input = input >> 16; } if ((input & 0xFF) == 0) { n = n + 8; input = input >> 8; } if ((input & 0xF) == 0) { n = n + 4; input = input >> 4; } if ((input & 3) == 0) { n = n + 2; input = input >> 2; } if ((input & 1) == 0) { ++n; } return n; } ---- ===== Using Builtin ===== GCC has **__builtin_clz**. lsb = __builtin_clz(pos); ---- ===== Using de Bruijn ===== const UINT64 DeBruijnSequence = 0x37E84A99DAE458FULL; int MultiplyDeBruijnBitPosition[] = { 0, 1, 17, 2, 18, 50, 3, 57, 47, 19, 22, 51, 29, 4, 33, 58, 15, 48, 20, 27, 25, 23, 52, 41, 54, 30, 38, 5, 43, 34, 59, 8, 63, 16, 49, 56, 46, 21, 28, 32, 14, 26, 24, 40, 53, 37, 42, 7, 62, 55, 45, 31, 13, 39, 36, 6, 61, 44, 12, 35, 60, 11, 10, 9, }; // Will return zero for b = 0. int BitScanForward(ulong b) { Debug.Assert(b > 0, "Target number should not be zero"); return multiplyDeBruijnBitPosition[((ulong)((long)b & -(long)b) * DeBruijnSequence) >> 58]; } **NOTE:** This is very fast. * The De Bruijn lookup table needs to be pre-calculated. * See: https://www.chessprogramming.org/De_Bruijn_Sequence_Generator. ---- ===== Using Logs ===== int lsb = (int)(Math.Log(v,2)); ---- ===== Using a Loop ===== int getLSB(ulong v) { int lsb = 0; while ((v >>= 1) != 0) { lsb++; } return lsb; } **NOTE:** This is very slow. ---- ===== Using MS C++ Compiler Built-in ===== #include unsigned char _BitScanForward( unsigned long * Index, unsigned long Mask ); unsigned char _BitScanForward64( unsigned long * Index, unsigned __int64 Mask ); ---- ===== Using .NET Core 3.0 ===== .NET Core 3.0 introduced hardware intrinsics: ulong value = 18; ulong result = System.Runtime.Intrinsics.X86.Bmi1.X64.TrailingZeroCount(value); Alternatively, the new **System.Numerics.Bitoperations** methods also use hardware intrinsics: int result2 = System.Numerics.BitOperations.TrailingZeroCount(value); ---- ===== Using the integer log base 2 of an integer with an 64-bit IEEE float ===== TODO int v; // 32-bit integer to find the log base 2 of int r; // result of log_2(v) goes here union { unsigned int u[2]; double d; } t; // temp t.u[__FLOAT_WORD_ORDER==LITTLE_ENDIAN] = 0x43300000; t.u[__FLOAT_WORD_ORDER!=LITTLE_ENDIAN] = v; t.d -= 4503599627370496.0; r = (t.u[__FLOAT_WORD_ORDER==LITTLE_ENDIAN] >> 20) - 0x3FF; **NOTE:** The code above loads a 64-bit (IEEE-754 floating-point) double with a 32-bit integer (with no padding bits) by storing the integer in the mantissa while the exponent is set to 2^52. * From this newly minted double, 2^52 (expressed as a double) is subtracted, which sets the resulting exponent to the log base 2 of the input value, v. * All that is left is shifting the exponent bits into position (20 bits right) and subtracting the bias, 0x3FF (which is 1023 decimal). * This technique only takes 5 operations, but many CPUs are slow at manipulating doubles, and the endianess of the architecture must be accommodated. ---- ===== References ===== http://graphics.stanford.edu/~seander/bithacks.html#IntegerLogDeBruijn https://www.chessprogramming.org/De_Bruijn_Sequence_Generator https://en.wikipedia.org/wiki/Bit_numbering https://docs.microsoft.com/en-us/cpp/intrinsics/bitscanforward-bitscanforward64?redirectedfrom=MSDN&view=msvc-160